2025 MI P1 Q4

2025 MI P1 Q4

6 marks

Three different blends of coffee beans – Blend \(A\), Blend \(B\) and Blend \(C\) – are sold at both M Café and I Café. The usual selling prices of the blends are the same at both cafés. The total cost of buying one package each of Blend \(A\), Blend \(B\) and Blend \(C\) is \(\$\) \(176\). During a holiday sale, the two cafés offered the following discounts:

CaféDiscounts given for each packageTotal price after the discount
Blend ABlend BBlend C
M Café\(15\%\)\(10\%\)\(5\%\)\(\$161.80\)
I Café\(7\%\)\(5\%\)\(2\%\)\(\$169.56\)
  1. Find the usual selling price of each package of Blend \(A\), Blend \(B\) and Blend \(C\) coffee beans respectively.[3]

Loyal customers of I Café receive an additional discount of \(x\%\) on the usual selling price of the packages for Blend \(A\) and Blend \(B\) only. (This loyalty discount is calculated as \(x\%\) of the usual price of each package and is subtracted from the sale prices above.)

I Café wants the total cost for its loyal customers to be less than the total cost at M Café when buying one of each package of the three blends.

  1. Form an inequality and find the smallest integer value of \(x\).[3]

Solution:

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Answer:(i) Blend A: \(32; Blend B: \)44; Blend C: $100. (ii) \(169.56-0.76x<161.80\), giving the smallest integer \(x=11\).

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