2025 JVSS PRELIMS P2 Q5

2025 JVSS PRELIMS P2 Q5

Secondary 4
6 marks
2025 Jurongville Secondary School Prelims A Math Paper 2

It is given that \(\cos \theta = \frac{5}{13}\), where \(0^\circ < \theta < 360^\circ\).

  1. Show that the value of \(2 - \sin^2 \theta\) is \(\frac{194}{169}\).[2]
  2. By finding the value of \(\sin^2 \theta\), find the exact value of \(\tan^2(90^\circ - \theta)\).[4]

Solution:

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Answer:(a) \(\frac{194}{169}\) (b) \(\frac{25}{144}\)

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