2025 JVSS PRELIMS P2 Q1

2025 JVSS PRELIMS P2 Q1

Secondary 4
8 marks
2025 Jurongville Secondary School Prelims A Math Paper 2
  1. Find the first 3 terms in the expansion of \( (1+3x)^8 \) in ascending powers of \(x\).[2]
  2. Hence determine the first 3 terms in the expansion of \( (2+6x+3x^2)^8 \).[3]
  3. Explain why there is no constant term in the expansion of \[ \left(2-\frac{1}{3x}\right)^2(1+3x)^8. \][3]

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Answer:(a) \(1+24x+252x^2\) (b) \(256+6144x+67584x^2\) (c) constant term \(=0\), so there is no constant term.

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