2025 JVSS PRELIMS P1 Q8

2025 JVSS PRELIMS P1 Q8

Secondary 4
9 marks
2025 Jurongville Secondary School Prelims A Math Paper 1

A curve has equation \(y=x\sqrt{x+k}+3\), where \(k\) is a positive constant.

  1. Show that \(\dfrac{dy}{dx}=\dfrac{3x+2k}{2\sqrt{x+k}}\).[3]
  2. Determine the nature of the stationary point on the curve.[6]

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Answer:(a) \(\frac{dy}{dx}=\frac{3x+2k}{2\sqrt{x+k}}\). (b) The stationary point is a minimum point.

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