The events \(A\) and \(B\) are such that \(\mathrm{P}(B) = \frac{1}{3}\), \(\mathrm{P}(A|B) = \frac{2}{5}\) and \(\mathrm{P}(A \cup B) = \frac{3}{5}\).
For a third event \(C\), it is given that \(\mathrm{P}(C) = \frac{1}{2}\) and that \(A\) and \(C\) are mutually exclusive.
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