2025 IGCSE Additional Mathematics October/November 0606/23 Q10

2025 IGCSE Additional Mathematics October/November 0606/23 Q10

11 marks

In this question the units are metres and seconds.

A particle moves along a straight line through a point \(A\).

Its displacement, \(s\), from \(A\) at time \(t\) is given by \(s=\dfrac{10t+100}{\sqrt{2t^2+100}}\).

The diagram shows the displacement–time graph for the first 30 seconds of the motion.

  1. Find the value of \(t\) when \(s\) is a maximum.[6]
  2. The particle passes through its starting point again at time \(t=T\).
    1. Find the total distance travelled by the particle during the first \(T\) seconds of its motion.[2]
    2. Use algebra to find \(T\).[3]

Solution:

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Answer:(a) 5 s (b)(i) \(10\sqrt6-20\text{ m}\), or 4.49 m (ii) \(T=20\text{ s}\)

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