2025 IGCSE Additional Mathematics October/November 0606/21 Q8

2025 IGCSE Additional Mathematics October/November 0606/21 Q8

13 marks

In this question, the units are metres and seconds.

A particle \(P\) is travelling in a straight line through a fixed point \(O\).

At time \(t\) its acceleration, \(a\), is given by \(a=(2t-3)^2\), where \(t\ge0\).

When \(t=3\), \(P\) has a velocity of 6.

    1. Find an expression for the velocity, \(v\), of \(P\) at time \(t\).[3]
    2. Find the time when \(P\) is at rest.[3]
      When \(t=\dfrac52\), the displacement of \(P\) from \(O\) is 4.
    3. Find the displacement of \(P\) from \(O\) when \(t=3\).[4]
  1. Use calculus to find the approximate change in \(v\) when \(t\) increases from \(\dfrac52\) by the small amount 0.02.[3]

Solution:

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Answer:(a)(i) \(v=\dfrac{(2t-3)^3}{6}+\dfrac32\) (ii) 0.460 s (iii) 6.10 m (b) \(0.08\text{ m s}^{-1}\)

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