The polynomial \(\mathrm p\) is such that \(\mathrm p(x)=2x^3+ax^2+13x+b\), where \(a\) and \(b\) are integers.
It is given that \(x+2\) is a factor of \(\mathrm p(x)\).
When \(\mathrm p(x)\) is divided by \(x+1\) there is a remainder of 6.
Sign in to view the step-by-step solution
Need help? Join our JC Math tuition classes.
Learn more