2025 IGCSE Additional Mathematics October/November 0606/11 Q11

2025 IGCSE Additional Mathematics October/November 0606/11 Q11

6 marks

The number of permutations of \(n\) items taken 4 at a time is equal to \(\dfrac16\) the number of permutations of \(2n\) items taken 3 at a time.

  1. Show that \(n\) satisfies the equation \(3n^2-19n+20=0\).[4]
  2. Hence find the value of \(n\).[2]

Solution:

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Answer:(a) Shown. (b) \(n=5\)

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