2025 IGCSE Additional Mathematics May/June 0606/23 Q4

2025 IGCSE Additional Mathematics May/June 0606/23 Q4

8 marks

The function \(\mathrm f\) is defined by \(\mathrm f(x)=2x-1\) for \(x\in\mathbb R\).

  1. Explain why the function \(\mathrm f^2\) can be formed.[1]
  2. On the axes, sketch the graph of \(y=|\mathrm f^2(x)|\).
    State any intercepts with the coordinate axes.[4]
  3. It is given that \(|\mathrm f^2(x)|\le ax+b\) for \(-1\le x\le3\) and for no other values of \(x\).
    Find the values of \(a\) and \(b\).[3]

Solution:

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Answer:(a) The range of \(\mathrm f\) equals its domain \(\mathbb R\). (b) \(y=|4x-3|\), intercepts \((0,3)\), \((\dfrac34,0)\). (c) \(a=\dfrac12,\ b=\dfrac{15}2\)

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