Functions \(\mathrm f\) and \(\mathrm g\) are such that
\(\mathrm f(x)=\dfrac{3x}{x+4}\quad\text{for}\hspace{0.5em}x>0\)
\(\mathrm g(x)=\sqrt{x+2}\quad\text{for}\hspace{0.5em}x>-2\).
Solve the equation \(\mathrm{fg}(x)=1\).[4]
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