2025 IGCSE Additional Mathematics May/June 0606/22 Q10

2025 IGCSE Additional Mathematics May/June 0606/22 Q10

9 marks

The first three terms, in descending powers of \(x\), in the expansion of \((3x^2-a)^n\left(1+\dfrac1{x^2}\right)^2\) can be written as \(729x^{12}+972x^{10}+bx^8\), where \(a\), \(b\) and \(n\) are constants.

Find the values of \(a\), \(b\) and \(n\).[9]

Solution:

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Answer:\(a=\dfrac13,\quad b=-108,\quad n=6\)

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