2025 IGCSE 0580 February/March P42 Q21

2025 IGCSE 0580 February/March P42 Q21

4 marks

\(OAB\) is a triangle.

\(C\) is the midpoint of \(OA\).

\(\overrightarrow{OC}=\mathbf{m}\) and \(\overrightarrow{CB}=\mathbf{n}\).

\(E\) lies on \(AB\) and \(AE:EB=4:5\).

Find, in terms of \(\mathbf{m}\) and \(\mathbf{n}\), the position vector of \(E\).

Give your answer in its simplest form.[4]

Solution:

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Answer:\(\dfrac{14}{9}\mathbf{m}+\dfrac49\mathbf{n}\).

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