2025 IGCSE 0580 February/March P42 Q17

2025 IGCSE 0580 February/March P42 Q17

9 marks

The diagram shows three points \(A\), \(B\) and \(C\) on horizontal ground.

The bearing of \(C\) from \(A\) is \(145^\circ\) and angle \(ACB=38^\circ\).

\(AC=65\text{ m}\) and \(BC=95\text{ m}\).

  1. Find the bearing of \(B\) from \(C\).[2]
  2. Show that \(AB=59.3\text{ m}\), correct to \(1\) decimal place.[3]
  3. Angle \(BAC\) is obtuse.
    Work out the bearing of \(B\) from \(A\).[4]

Solution:

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Answer:(a) \(287^\circ\). (b) \(AB=59.3\text{ m}\) (1 d.p.). (c) \(244.6^\circ\).

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