2025 IGCSE 0580 February/March P22 Q23

2025 IGCSE 0580 February/March P22 Q23

6 marks
  1. Simplify \(\left(\dfrac{x^2}{4}\right)^{\frac32}\).[2]
  2. \(16^x\times\left(\dfrac12\right)^x=4^{x+3}\)
    Find the value of \(x\).[4]

Solution:

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Answer:(a) \(\dfrac{|x|^3}{8}\), equal to \(\dfrac{x^3}{8}\) for \(x\geq0\). (b) \(x=6\).

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