2025 IGCSE 0580 May/June P42 Q20

2025 IGCSE 0580 May/June P42 Q20

13 marks

The diagram shows a quadrilateral \(ABCD\).

\(CD=10\text{ m}\) and \(DB=12\text{ m}\).

Angle \(DBA=90^\circ\), angle \(CDB=56^\circ\) and angle \(ADB=34^\circ\).

  1. Calculate the length of \(AB\).[2]
  2. Calculate the area of the quadrilateral \(ABCD\).[3]
  3. Calculate the perimeter of the quadrilateral \(ABCD\).[5]
  4. Calculate the shortest distance from \(B\) to the line \(AD\).[3]

Solution:

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Answer:(a) \(8.09\text{ m}\). (b) \(98.3\text{ m}^2\). (c) \(43.0\text{ m}\). (d) \(6.71\text{ m}\).

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