2025 IGCSE 0580 May/June P23 Q15

2025 IGCSE 0580 May/June P23 Q15

6 marks
  1. Simplify.
    \(\sqrt{27}+\sqrt{12}\)[2]
  2. \(\dfrac{40\sqrt8}{5\sqrt2}=k\), where \(k\) is an integer.
    Find the value of \(k\).[2]
  3. Rationalise the denominator.
    \(\dfrac1{3-\sqrt5}\)[2]

Solution:

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Answer:(a) \(5\sqrt3\). (b) \(16\). (c) \(\dfrac{3+\sqrt5}{4}\).

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