2025 IGCSE 0580 May/June P21 Q18

2025 IGCSE 0580 May/June P21 Q18

10 marks

One day, Anya runs \(12\text{ km}\) at a speed of \(x\text{ km/h}\).

The next day she walks \(10\text{ km}\) at a speed of \((x-4)\text{ km/h}\).

  1. Write down an expression, in terms of \(x\), for the time she spends running.[1]
  2. Write down an expression, in terms of \(x\), for the time she spends walking.[1]
  3. The time Anya spends walking is \(1\) hour more than the time she spends running.
    Write an equation in terms of \(x\) and show that it simplifies to \(x^2-2x-48=0\).[4]
  4. Use factorisation to solve the equation \(x^2-2x-48=0\).[3]
  5. Find the time Anya spends running.[1]

Solution:

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Answer:(a) \(\dfrac{12}{x}\text{ h}\). (b) \(\dfrac{10}{x-4}\text{ h}\). (c) \(\dfrac{10}{x-4}-\dfrac{12}{x}=1\Rightarrow x^2-2x-48=0\). (d) \(x=-6\) or \(8\). (e) \(1.5\text{ h}\).

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