Show that \(x - 1\) is a factor of \(2x^3 - 5x^2 + x + 2\).
Hence, factorise \(2x^3 - 5x^2 + x + 2\) completely.
[5]Solve the equation \(2\left(\mathrm{e}^{2y - 2}\right) - 5\left(\mathrm{e}^{y - 1}\right) + 2\mathrm{e}^{1 - y} + 1 = 0\).
Leave your answers in exact form.
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