The equation of a curve is given by \(y = P - Q \cos 4x - \frac{1}{2} \sin 2x\).
Given that \(\frac{\mathrm{d}^2 y}{\mathrm{d}x^2} + 4y = 15 \cos 4x - 8\), find the values of the constants \(P\) and \(Q\).
[4]With the values of the constants \(P\) and \(Q\) found in part (a), find the equation of the normal to the curve at \(x = \frac{\pi}{2}\). Leave your equation in terms of \(\pi\).
[4]Need help? Join our JC Math tuition classes.
Learn more