State the coordinates of the turning points of the graph of \(y = x^3 - 3x^2 - 9x + 5\).[1]
The function \(\mathrm{f}\) is defined by\[\mathrm{f}(x) = x^3 - 3x^2 - 9x + 5, x \in \mathbb{R}, x \leq a\] where \(a\) is a constant. Find the largest possible value of \(a\) such that \(\mathrm{f}^{-1}\) exists, and state the domain of \(\mathrm{f}^{-1}\) in this case.[2]
The function \(\mathrm{g}\) is defined by\[\mathrm{g}(x) = \frac{1 - 2x}{x + 2}, x \in \mathbb{R}, x \neq -2.\]
Find \(\mathrm{g}^2(x)\).[2]
Hence find the possible expressions of \(\mathrm{g}^n(x)\), where \(n\) is a positive integer.[2]
The function \(\mathrm{h}\) is defined by\[\mathrm{h}(x) = x^2, x \in \mathbb{R}, x \leq 0.\]
Explain why the composite function \(\mathrm{g}\mathrm{h}\) exists.[2]
Find the range of \(\mathrm{g}\mathrm{h}\).[2]
Solution:
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Answer:(a)(i) \((-1,10)\), \((3,-22)\). (ii) \(a=-1\), \(D_{\mathrm f^{-1}}=(-\infty,10]\). (b)(i) \(\mathrm g^2(x)=x\), \(x\ne-2\). (ii) Even \(n\): \(x\); odd \(n\): \(\frac{1-2x}{x+2}\), with \(x\ne-2\) in both cases. (c)(i) \([0,\infty)\subset D_{\mathrm g}\), so the composite exists. (ii) \((-2,\frac{1}{2}]\).