Solve the inequality $x+1 \frac{1}{x-1}$ giving your answer in exact form.[3] Hence solve, in

Question

Solve the inequality $x+1 > \frac{1}{x-1}$ giving your answer in exact form.[3] Hence solve, in exact form, $\mathrm{e}^x+1 > \frac{1}{\mathrm{e}^x-1}$[2]

Accepted Answer

(a)$-\sqrt2\sqrt2$ (b) x $\frac{1}{2}\ln 2$

2025 EJC P1 Q1

2025 EJC P1 Q1