It is given that $y=\frac{2x-1}{\sqrt{x+2}}$ with natural real domain $xq$. State the v

Question

It is given that $y=\frac{2x-1}{\sqrt{x+2}}$ with natural real domain $x>q$. State the value of $q$.[1] Find $\frac{dy}{dx}$.[3] State whether $y=\frac{2x-1}{\sqrt{x+2}}$ is an increasing or decreasing function. Explain your answer clearly.[2]

Accepted Answer

(a) $q=-2$ (b) $\frac{dy}{dx}=\frac{2x+9}{2(x+2)^{\frac{3}{2}}}$ (c) Increasing for $x>-2$, since $\frac{dy}{dx}>0$.

2025 CGS PRELIMS P1 Q6

2025 CGS PRELIMS P1 Q6

Solution:

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