Solve the equation $\log_5 (3y + 1) - \frac{1}{\log_y 5} + \log_2 8 = 4$.[4] By expressing the equ

Question

Solve the equation $\log_5 (3y + 1) - \frac{1}{\log_y 5} + \log_2 8 = 4$.[4] By expressing the equation $\ln(6\mathrm{e}^x + 1) + x = 0$ as a quadratic equation in $\mathrm{e}^x$, solve the equation $\ln(6\mathrm{e}^x + 1) + x = 0$, giving values of $x$ in logarithmic form.[4]

Accepted Answer

(a) $y=\dfrac12$ (b) $x=\ln\left(\dfrac13\right)=-\ln3$

(A Math) 2025 CCHY PRELIMS P2 Q6

(A Math) 2025 CCHY PRELIMS P2 Q6

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