(ABCD) is a square and (angle EDC=angle ECD=55^circ).

Prove that triangle (AEB) is an isosceles triangle.[4]

Question

(ABCD) is a square and (angle EDC=angle ECD=55circ). Prove that triangle (AEB) is an isosceles triangle.

Accepted Answer

$AE=BE$; triangle $AEB$ is isosceles.

2025 CHS PRELIMS P1 Q23