Mark clearly a possible point which is inside the triangle, equidistant from (X) and (Y), and nearer to (YZ) than (XY). Label this point (P).[1]
The point (M) is such that (angle YZM=100^circ) and (XM=5 ext{ cm}). Mark and label the point (M) at the position that is closer to point (Z). Measure and write down the length (ZM).[2]
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Answer:Required constructions and nearer intersection \(M\).