The diagram shows a rectangle \(ABCD\) and an isosceles triangle \(PAB\) in which \(PA=PB\). \(PD\) and \(PC\) meet \(AB\) at \(Q\) and \(R\) respectively.
Prove that triangle \(PDC\) is an isosceles triangle.[3]
Sign in to view the step-by-step solution
Need help? Join our JC Math tuition classes.
Learn more