Construct triangle \(ABC\) where \(AB=5.8\text{ cm}\), \(BC=7\text{ cm}\) and \(AC=9.5\text{ cm}\). Line \(AB\) has been drawn.[1]
On the same diagram, construct
the perpendicular bisector of \(AB\),[1]
the angle bisector of angle \(CAB\).[1]
Mark clearly a possible point which lies inside the triangle, equidistant from \(A\) and \(B\), and is nearer to \(AC\) than \(AB\). Label this point \(X\).[1]
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Answer:Required construction with \(X\) in the stated locus