A particle moves in a straight line with a fixed point \(O\). The velocity of the particle, \(v\) m/s, is given by \[v = \frac{25}{2t+1} + 10\] where&nbsp;\(t\) is time in seconds after passing \(O\).
<ol class="abc-list"><li><div class="list-item-content">Explain why the particle never change its direction of motion and will eventually travel at a speed close to \(10\) m/s.[2]</div></li></ol>
(b) Find the acceleration of the particle at t = 2[2]
(c) Calculate the distance travelled by the particle in the fifth second of its motion.[4]

A particle moves in a straight line with a fixed point \(O\). The velocity of the particle, \(v\) m/s, is given by \[v = \frac{25}{2t+1} + 10\] where \(t\) is time in seconds after passing \(O\).

Explain why the particle never change its direction of motion and will eventually travel at a speed close to \(10\) m/s.

**(b)**    Find the acceleration of the particle at t = 2

**(c)** Calculate the distance travelled by the particle in the fifth second of its motion.

2025 CHS PRELIMS P2 Q9

2025 CHS PRELIMS P2 Q9