2025 Bedok View Secondary School Prelims A Math Paper 1
Find the value of the constant \(k\) such that the line \(y = kx + 6\) is a tangent to the curve \(2x^2 - xy = 3\).[3]
Solve \((4 - 2\sqrt{2})x + \sqrt{2} = 3x\sqrt{2} - 1\), giving your answer in the form \(a\sqrt{2} + b\), where \(a\) and \(b\) are rational numbers.[4]
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