The function $f$ is given by $f(x)=\dfrac{x+a}{x^2+3}$. Find $f'(x)$.[2] It is given that&nbsp

Question

The function $f$ is given by $f(x)=\dfrac{x+a}{x^2+3}$. Find $f'(x)$.[2] It is given that $f$ increases precisely for $b<x<1$. Find the values of $a$ and $b$.[4]

Accepted Answer

(a) $f'(x)=\dfrac{-x^2-2ax+3}{(x^2+3)^2}$ (b) $a=1,\ b=-3$

2025 BVSS PRELIMS P1 Q5

2025 BVSS PRELIMS P1 Q5

Solution:

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