2025 BDS PRELIMS P2 Q9

2025 BDS PRELIMS P2 Q9

Secondary 4
12 marks
2025 Bedok South Secondary School Prelims A Math Paper 2

The table below shows experimental values of two variables \(x\) and \(y\).

\(x\)123456
\(y\)2.201.741.711.831.871.96

The variables \(x\) and \(y\) are related by the equation \(\dfrac{y}{a}=\dfrac{1}{x}+b\sqrt{x}\), where \(a\) and \(b\) are constants.

One value of \(y\) has been recorded incorrectly.

  1. Show how \(\dfrac{y}{a}=\dfrac{1}{x}+b\sqrt{x}\) is transformed to plot a graph of \(xy\) against \(x\sqrt{x}\).[1]
  2. On the grid provided below, draw a straight line graph of \(xy\) against \(x\sqrt{x}\) for the given data.[2]
  3. Using your graph,
    1. find an approximate value of \(y\) to replace the incorrect value,[2]
    2. estimate the value of \(a\) and of \(b\),[3]
    3. find the value of \(y\) when \(x=2.52\).[2]
  4. A pair of values of \(x\) and \(y\) is considered acceptable only if the \(xy\) value is within \(2\%\) vertical difference from the straight line. A student recorded a pair of values such that \(x=4.50\) and \(y=1.86\). Verify whether the recorded values by the student are acceptable.[2]

Solution:

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Answer:(a) \(xy=a+abx\sqrt{x}\). (b) \(xy\approx0.700x\sqrt{x}+1.50\). (c)(i) \(1.78\). (c)(ii) \(a\approx1.50\), \(b\approx0.467\). (c)(iii) \(y\approx1.71\). (d) Not acceptable: vertical difference \(\approx2.30\%\).

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