A square of area $ \left(11 + \sqrt{120} \right)\ \text{cm}^2$ has a length of \( \left(\sqrt{a} +

Question

A square of area $ \left(11 + \sqrt{120} \right)\ \text{cm}^2$ has a length of $ \left(\sqrt{a} + \sqrt{b} \right)\ \text{cm}$, where $a < b$. Without using a calculator, find the values of $a$ and $b$.[5]

Accepted Answer

$a=5,\ b=6$

Surds - Applications of Surds

Surds - Applications of Surds

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