2025 ASRJC Promo Q5

2025 ASRJC Promo Q5

Junior College 1
9 marks

The function f is defined by \( \mathrm{f}:x\mapsto \frac{2x+a}{x+b},\quad x\in\mathbb{R}, x\ne -b\text{ and}\hspace{0.5em}a\ne 2b,\)

where \(b\) is a real constant.

    1. Find \(\mathrm{f}^{-1}(x)\) in terms of \(a\) and \(b\). State the domain of \(\mathrm{f}^{-1}\).[2]
      The function f is such that \(\mathrm{f}(x)=\mathrm{f}^{-1}(x)\) for all \(x\) in the domain of f.
    2. Find the possible values of \(a\) and \(b\).[2]
  1. The function g is defined by
    \(\mathrm{g}:x\mapsto 7+\sqrt{x-3},\quad x\in\mathbb{R},\ x\ge 3.\)
    Using the values \(a=-1\) and \(b=1\),
    1. Show that fg exists.[2]
    2. Find the value of fg(7).[1]
    3. Find the exact range of fg.[2]

Solution:

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Answer:(a)(i) \(\mathrm{f}^{-1}(x)=\dfrac{a-bx}{x-2}\), \(x\ne2\) (a)(ii) \(b=-2,\ a\ne-4\) (b)(ii) \(\dfrac{17}{10}\) (b)(iii) \(\left[\dfrac{13}{8},2\right)\)

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