2025 ASRJC P1 Q1
2025 ASRJC P1 Q1
4 marks
A cubic curve passes through the points \((2, 3)\) and \((-3, -22)\). Find the equation of the curve if it has a stationary point at \((1, -6)\).[4]
Solution:
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Answer:The equation of the curve is y = \(2x^3 + x^2 -8x-1\)
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