2025 ACJC P1 Q5

2025 ACJC P1 Q5

Junior College 2
6 marks

Relative to the origin \(O\), the points \(A\) and \(B\) have non-zero and non-parallel position vectors \(\mathbf{a}\) and \(\mathbf{b}\) respectively. The plane \(p\) has equation \(\mathbf{r} \cdot \mathbf{n} = 0\).

  1. Given that \(\mathbf{a} \cdot \mathbf{n} = \mathbf{b} \cdot \mathbf{n} \neq 0\), show that \(\overrightarrow{AB}\) is perpendicular to \(\mathbf{n}\). Hence, describe the geometrical relationship between \(\overrightarrow{AB}\) and the plane \(p\).[2]
  2. Write down the equation of a line parallel to \(\overrightarrow{AB}\) that is contained in the plane \(p\).[1]
  3. The point \(F\) is the foot of perpendicular from a point \(C\) with position vector \(\mathbf{c}\) to the plane \(p\). Find the position vector of point \(F\), giving your answer in terms of \(\mathbf{c}\) and \(\mathbf{n}\).[3]

Solution:

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Answer:(a) \(\therefore \overrightarrow{AB}\) is parallel to the plane \(p\) (b) \(\mathbf{r} = \lambda(\mathbf{b} - \mathbf{a})\) (Since origin lies on \(p\).) (c) \(\therefore \overrightarrow{OF} = \mathbf{c} - \left( \frac{\mathbf{c} \cdot \mathbf{n}}{\vert{}\mathbf{n}\vert{}^2} \right) \mathbf{n}\) or \(\therefore \overrightarrow{OF} = \overrightarrow{OC} + \overrightarrow{CF} = \mathbf{c} - \frac{(\mathbf{c} \cdot \mathbf{n})}{\vert{}\mathbf{n}\vert{}^2} \mathbf{n}\)

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