2025 ACJC P1 Q11

2025 ACJC P1 Q11

Junior College 2
12 marks

The curve \(C\) is defined by the parametric equations \(x=at^2\), \(y=\frac{a}{t}\), \(t \neq 0\), where \(a\) is a positive constant.

  1. Show that the equation of the tangent to the curve at the point \(P\left(ap^2, \frac{a}{p}\right)\) is \(2p^3y+x=3ap^2\).[2]
  2. Find the equations of the tangents to \(C\) at the points where \(x=a\). Find also the acute angle between these tangents.[3]
    1. Show that \((q-p)^2(q+2p)=q^3-3p^2q+2p^3\).[1]
    2. The tangent to the curve at \(P\) cuts the curve again at \(Q\left(aq^2, \frac{a}{q}\right)\). Find \(q\) in terms of \(p\).[3]

The following diagram shows the graph of \(C\) for \(a=1\), and the Cartesian equation of the curve \(C\) is \(xy^2=1\). The tangent to \(C\) at the point \(\left(p^2, \frac{1}{p}\right)\) cuts the curve again at the point \(\left(4p^2, -\frac{1}{2p}\right)\).

The region \(S\) is bounded by the tangent to \(C\) at the point \(\left( p^2, \frac{1}{p} \right)\), the curve \(C\) and the line

\(x = p^2\)

  1. Find the area of \(S\) in terms of \(p\).[3]

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Answer:(a) \(2p^3y+x=3ap^2\) (b) \(y=-\frac{x}{2}+\frac{3a}{2}\), \(y=\frac{x}{2}-\frac{3a}{2}\), acute angle \(\tan^{-1}\!\left(\frac{4}{3}\right)\approx53.1^\circ\) (c)(i) \((q-p)^2(q+2p)=q^3-3p^2q+2p^3\) (c)(ii) \(q=-2p\) (d) \(\frac{11p}{4}\)

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