2024 VJC H1 Q1

2024 VJC H1 Q1

4 marks

The curve \(C\) has equation \(y = \frac{x - 1}{x}\). Find the value of \(a\) such that the line \(L\) with equation \(y = ax + 13\) is a tangent to \(C\). Hence find the value of \(x\) at the point where \(L\) is a tangent to \(C\).[4]

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Answer:A = 36, \(x=-\frac{1}{6}\)

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