For events \(A\) and \(B\), it is given that \(P\left( A \right)=\frac{1}{8}\), \(P\left( A\cup B \right)=\frac{9}{16}\) and \(P\left( A\cap {B}' \right)=\frac{1}{16}\).
For a third event \(C\), it is given that \(P\left( C \right)=\frac{3}{8}\), \(P\left( A\cap B\cap C \right)=\frac{1}{64}\) and \(C\) is independent of \(A\).
Video solution locked
A free account saves your progress; this video needs a course plan.
680+ questions here come with free worked solutions. A free account saves your questions and progress; this one needs a course plan.
Create a free account to practise similar questions.
Need help? Join our JC Math tuition classes.
Learn more