2024 NJC P2 Q6

2024 NJC P2 Q6

4 marks
Prelims

For a positive integer \(n\), it is given that \(\mathrm{P}\left( A=n \right)=0.009542\) and \(\mathrm{P}\left( A=n+1 \right)=0.004090\), where \(A\sim\mathrm{B}\left( 2n+1,p \right)\). Show that \(p\) satisfies an equation of the form \(\frac{p}{1-p}=k\), where \(k\) is a constant to be determined. Hence find the value of \(n\) and the variance of \(A\).[4]

Video Solution:

Video Solution

Video solution locked

A free account saves your progress; this video needs a course plan.

Solution:

Solution locked

680+ questions here come with free worked solutions. A free account saves your questions and progress; this one needs a course plan.

Answer:\({p=0.300\text{ (3 s.f.)}}\) , \({n=17}\) and \({\mathrm{Var}(A)=7.35\text{ (3 s.f.)}}\)

Need help? Join our JC Math tuition classes.

Learn more