For a positive integer \(n\), it is given that \(\mathrm{P}\left( A=n \right)=0.009542\) and \(\mathrm{P}\left( A=n+1 \right)=0.004090\), where \(A\sim\mathrm{B}\left( 2n+1,p \right)\). Show that \(p\) satisfies an equation of the form \(\frac{p}{1-p}=k\), where \(k\) is a constant to be determined. Hence find the value of \(n\) and the variance of \(A\).[4]
Video solution locked
A free account saves your progress; this video needs a course plan.
680+ questions here come with free worked solutions. A free account saves your questions and progress; this one needs a course plan.
Create a free account to practise similar questions.
Need help? Join our JC Math tuition classes.
Learn more