2024 MI PRU2 P1 Q8

2024 MI PRU2 P1 Q8

8 marks
  1. Sketch, on the same axes, the graphs of \(y = -2 + 3^x\) and \(y = \ln(1 - x^3)\), stating clearly the equations of any asymptotes.[4]
  2. Hence solve the inequality \(\ln(1 - x^3) \le -2 + 3^x\).[2]
  3. Using your result in part (ii), solve the inequality \(\ln(1 + x^3) \le -2 + \frac{1}{3^x}\).[2]

Solution:

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Answer:(i) Sketch shown; asymptotes \(y=-2\), \(x=1\). (ii) \(r\le x<1\). (iii) \(-1<x\le-r\), where \(r=0.5461662555\ldots\) is the intersection abscissa.

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