The $n$th term of a sequence $u_1$, $u_2$, $u_3$, $\ldots$ is given by \(u_n = an^3 + \fra

Question

The $n$th term of a sequence $u_1$, $u_2$, $u_3$, $\ldots$ is given by $u_n = an^3 + \frac{b}{n} + c$, where $a$, $b$ and $c$ are constants. Given that $u_1 = 3$, $u_2 = 22$ and the sum of the first 3 terms is 95, find the values of $a$, $b$ and $c$.

Accepted Answer

$a=\dfrac52,\quad b=-3,\quad c=\dfrac72$

2024 MI PRU2 P1 Q1

2024 MI PRU2 P1 Q1

Solution:

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