2024 MI H1 Q6

2024 MI H1 Q6

12 marks
Design of a viewing platform
Design of a viewing platform
  1. The diagram below shows the design of a viewing platform. The viewing platform is designed by removing two identical semi-circles at the ends of a rectangle. The radius of the semi-circle is \(x\) m and the length of the rectangle is \(y\) m. The enclosed area of the viewing platform is \(10800\) m\({}^2\).
    1. Show that \(y = \frac{5400}{x} + \frac{\pi}{2}x\).[2]
    2. Tiles are to be laid along the perimeter, \(P\) m, of the enclosed area of the viewing platform. Hence find an expression for \(P\), in terms of \(x\).[2]
    3. Find the exact value of \(x\) which gives \(P\) a minimum value. You need not justify that \(P\) is a minimum value.[3]
Region R bounded by a line and a curve
Region R bounded by a line and a curve
  1. In another design, the area of the viewing platform, region \(R\), is bounded by the line \(y = -x + 4\), the curve \(y = \sqrt{11 - 2x}\) and the \(x\)-axis.
    1. Given that both the line \(y = -x + 4\) and the curve \(y = \sqrt{11 - 2x}\) intersect at point \(A\), verify that the coordinates of \(A\) is \((1, 3)\).[1]
    2. Hence, without using a graphing calculator, find the area of region \(R\).[4]

Solution:

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Answer:(a)(ii)\(3\pi x+\frac{10800}{x}\) (a)(iii)\(\frac{60}{\sqrt{\pi}}\) (b)(ii)4.5

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