A curve $C$ has equation $\mathrm{f}(x) = \frac{a}{x^2} + bx + c$, where $a$, $b$ and \

Question

A curve $C$ has equation $\mathrm{f}(x) = \frac{a}{x^2} + bx + c$, where $a$, $b$ and $c$ are constants. It is given that $C$ passes through the points $(-1, 4)$ and $(2, -11)$ and the curve of $y = \frac{1}{\mathrm{f}(x)}$ has a vertical asymptote with equation $x = 1$. Find the equation of $C$.[4]

Accepted Answer

$y=\frac{12}{x^2}-2x-10$, with $x\ne0$.

2024 JPJC Promo Q3

2024 JPJC Promo Q3

Solution:

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