By writing \(x=\mathrm{A}\left( 8x-8 \right)+\mathrm{B}\), where \({A}\) and \({B}\) are constants, find \(\displaystyle \displaystyle\int_{0}^{1}{\frac{x}{4{{x}^{2}}-8x+5}}\ \mathrm{d}x\), giving your answer in the form \(p\ln q+r{{\tan }^{-1}}s\), where \(p\), \(q\), \(r\) and \(s\) are values to be determined.[5]
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