2024 JPJC Promo Q11

2024 JPJC Promo Q11

9 marks
Promo

Referred to the origin \(O\), points \(A\) and \(B\) have position vectors \(\mathbf{a}\) and \(\mathbf{b}\) respectively, where \(\mathbf{a}\) and \(\mathbf{b}\) are non-zero and non-parallel vectors. Point \(C\) is the midpoint of \(OA\) and point \(D\) lies on \(BC\) such that \(BD:DC=2:3\).

  1. Find the position vectors \(\overrightarrow{OC}\) and \(\overrightarrow{OD}\), giving your answers in terms of \(\mathbf{a}\) and \(\mathbf{b}\).[2]
  2. Find the area of triangle \(OCD\) in the form of \(k\left| \mathbf{a}\times \mathbf{b} \right|\), where \(k\) is a constant to be found.[3]
  3. Given that \(\left| \mathbf{a} \right|=2\), \(\left| \mathbf{b} \right|=\sqrt{2}\) and \(\angle AOB=\frac{\pi }{4}\) radian, using scalar product, show that \(CD\) is perpendicular to \(OA\).[3]
  4. Given instead that \(\mathbf{a}\) is a unit vector, give a geometrical interpretation of \(\left| \mathbf{a}\cdot \mathbf{b} \right|\).[1]

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Answer:(i) \(\overrightarrow{OC}=\frac12\mathbf a\), \(\overrightarrow{OD}=\frac15\mathbf a+\frac35\mathbf b\). (ii) \(\frac3{20}|\mathbf a\times\mathbf b|\), so \(k=\frac3{20}\). (iii) \(CD\perp OA\). (iv) The length of the orthogonal projection of \(OB\) onto the line through \(O\) parallel to \(OA\).

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