2024 IGCSE Additional Mathematics October/November 0606/22 Q11

2024 IGCSE Additional Mathematics October/November 0606/22 Q11

9 marks

In this question \(\mathbf i\) is a unit vector in the positive \(x\)-direction and \(\mathbf j\) is a unit vector in the positive \(y\)-direction. Time is in seconds and distances are in metres.

The diagram shows the initial positions and velocities of two particles, \(A\) and \(B\), that move in the \(x\)-\(y\) plane.

Particle \(A\) starts from the origin \(O\) at time \(t=0\). It moves with constant speed \(10\text{ m s}^{-1}\) in the direction \(60^\circ\) above the \(x\)-axis.

  1. Find the exact values of the components of the velocity of particle \(A\) in the \(x\)-direction and the \(y\)-direction.[2]
  2. Find, in terms of \(t\), the position vector of particle \(A\) at time \(t\).[1]

Particle \(B\) starts from the point \((2\sqrt3,9)\) at time \(t=0\). It moves with constant speed \(\dfrac53\text{ m s}^{-1}\) parallel to the positive \(x\)-axis.

  1. Find, in terms of \(t\), the position vector of particle \(B\) at time \(t\).[2]
  2. Hence show that the particles collide.[4]

Solution:

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Answer:(a) \(5,5\sqrt3\text{ m s}^{-1}\). (b) \(5t\mathbf i+5\sqrt3t\mathbf j\). (c) \((2\sqrt3+\dfrac53t)\mathbf i+9\mathbf j\). (d) Collision at \((3\sqrt3,9)\), \(t=\dfrac{3\sqrt3}5\) s.

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