2024 IGCSE Additional Mathematics May/June 0606/22 Q4

2024 IGCSE Additional Mathematics May/June 0606/22 Q4

7 marks

The polynomial \(\mathrm{p}\) is such that \(\mathrm{p}(x)=6x^3+x^2-12x+5\).

  1. Find the remainder when \(\mathrm{p}(x)\) is divided by \(x-2\).[1]
    1. Show that \(2x-1\) is a factor of \(\mathrm{p}(x)\).[1]
    2. Hence write \(\mathrm{p}(x)\) as a product of linear factors.[3]
    3. Hence solve the equation \(6\sin^3\theta+\sin^2\theta-12\sin\theta+5=0\) for \(0^\circ\leq\theta\leq90^\circ\).[2]

Solution:

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Answer:(a) \(33\). (b)(i) \(\mathrm{p}\left(\dfrac12\right)=0\). (ii) \((2x-1)(3x+5)(x-1)\). (iii) \(\theta=30^\circ,90^\circ\).

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