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2024 IGCSE Additional Mathematics May/June 0606/21 Q10
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2024 IGCSE Additional Mathematics May/June 0606/21 Q10
8 marks
Show that \((\tan x+\sec x)^2\) can be written as \(\dfrac{1+\sin x}{1-\sin x}\).
[4]
Hence solve the equation \((\tan3\theta+\sec3\theta)^2=6\) for \(0^\circ\leq\theta\leq180^\circ\).
[4]
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Answer:
(a) \(\dfrac{1+\sin x}{1-\sin x}\), as shown. (b) \(\theta=15.2^\circ,44.8^\circ,135.2^\circ,164.8^\circ\).
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