2024 IGCSE Additional Mathematics May/June 0606/13 Q9

2024 IGCSE Additional Mathematics May/June 0606/13 Q9

10 marks

In this question, all lengths are in metres, and time, \(t\), is in seconds.

A particle \(P\) moves in a straight line such that, \(t\) seconds after leaving a fixed point \(O\), its displacement, \(s\), is given by \(s=4t-4\cos2t+4\).

  1. Find the velocity, \(v\), of \(P\) at time \(t\).[2]
  2. On the axes, sketch the velocity–time graph for \(P\) for \(0\leq t\leq\pi\), stating the intercepts with the axes in exact form.[5]
  3. Find the acceleration of \(P\) at time \(t\).[1]
  4. Find the times when the acceleration of \(P\) is zero for \(0\leq t\leq\pi\). Give your answers in terms of \(\pi\).[2]

Solution:

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Answer:(a) \(v=4+8\sin2t\,\mathrm{m\,s}^{-1}\). (b) Sketch shown; intercepts \((0,4),(\dfrac{7\pi}{12},0),(\dfrac{11\pi}{12},0)\). (c) \(a=16\cos2t\,\mathrm{m\,s}^{-2}\). (d) \(t=\dfrac\pi4,\dfrac{3\pi}4\).

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